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Velocity and Online Solutions

COSMOS: Total Online Solutions Manual Organization System

Part 11, Answer 2 .

back button = t3 − (t − 2) m

2

v= a= (a) Time at a = zero.

dx sama dengan 3t 2 − two ( big t − two ) m/s dt dv = 6t − two m/s two dt

zero = 6t0 − two = 0 t0 = 1 a few

t0 sama dengan 0. 333 s

(b)

Corresponding situation and velocity.

⎛1⎞ ⎛1 ⎞ times = ⎜ ⎟ − ⎜ − 2 ⎟ = − 2 . 741 m ⎝3� ⎝3 � 3 a couple of

x sama dengan − installment payments on your 74 m

⎛1⎞ ⎛1 ⎞ sixth is v = several ⎜ ⎟ − a couple of ⎜ − 2 ⎟ = 3. 666 m/s ⎝3� ⎝3 �

two

v sama dengan 3. 67 m/s

Vector Mechanics intended for Engineers: Statics and Characteristics, 8/e, Ferdinand P. Ale, E. Russell Johnston, Jr., Elliot Ur. Eisenberg, William E. Clausen, David Mazurek, Phillip T. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Total Online Solutions Manual Organization System

Part 11, Remedy 3.

Position:

Velocity: x = 5t 4 − 4t 3 + 3t − two ft v= a= dx = 20t 3 − 12t 2 + a few ft/s dt dv sama dengan 60t two − 24t ft/s 2 dt

Speeding:

When big t = a couple of s,

times = ( 5 )( 2 ) − ( 4 )( 2 ) − ( 3)( 2 ) − 2 sixth is v = ( 20 )( 2 ) − (12 )( two ) + 3 a = ( 60 )( 2 ) − ( 24 )( 2 ) 2 several 2

5

3

x = 52 ft versus = 121 ft/s a = 192 ft/s a couple of

Vector Technicians for Designers: Statics and Dynamics, 8/e, Ferdinand G. Beer, At the. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

NATUREL: Complete Online Solutions Manual Organization System

Chapter 11, Solution 5.

Position:

Speed: x sama dengan 6t four + 8t 3 − 14t a couple of − 10t + of sixteen in.

v=

a=

dx = 24t 3 + 24t a couple of − 28t − twelve in. /s dt

dv = 72t 2 & 48t − 28 in. /s two dt

Velocity:

When capital t = a few s,

times = ( 6 )( 3) + ( 8 )( 3) − (14 )( 3) − (10 )( 3) + sixteen v = ( twenty four )( 3) + ( 24 )( 3) − ( 28 )( 3) − 10 a sama dengan ( seventy two )( 3) + ( 48 )( 3) − 28 two 3 two

4

3

2

x = 562 in.! sixth is v = 770 in. /s! a sama dengan 764 in. /s 2!

Vector Mechanics for Technicians: Statics and Dynamics, 8/e, Ferdinand P. Beer, At the. Russell Johnston, Jr., Elliot R. Eisenberg, William At the. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

NATUREL: Complete On the net Solutions Manual Organization Program

Chapter 11, Solution a few.

Position:

Speed: x sama dengan 500sin kt mm v= a= and k = 10 rad/s kt = (10 )( 0. 05 ) sama dengan 0. 5 rad back button = 500sin ( 0. 5 ) dx sama dengan 500k cos kt mm/s dt dv = − 500k two sin kt mm /s 2 dt

Acceleration: When ever t = 0. 05 s,

times = 240 mm! sixth is v = 4390 mm/s! a = − 24. zero × 103 mm/s 2!

v = ( five-hundred )(10 ) cos ( 0. 5 )

a = − ( 500 )(10 ) sin ( 0. a few )

two

Vector Mechanics for Designers: Statics and Dynamics, 8/e, Ferdinand S. Beer, At the. Russell Johnston, Jr., Elliot R. Eisenberg, William At the. Clausen, David Mazurek, Phillip J. Cornwell © 3 years ago The McGraw-Hill Companies.

COSMOS: Complete On the web Solutions Manual Organization Program

Chapter eleven, Solution six.

Position: Where Let

back button = 50sin k1t − k2t 2 mm k1 = 1 rad/s dθ = (1 − t ) rad/s dt x = 50sin θ millimeter v= and k2 = 0. a few rad/s a couple of

(

)

θ sama dengan k1t − k2t two = big t − zero. 5t a couple of rad

and d 2θ = −1 rad/s 2 dt two

Position:

Speed:

Acceleration:

dx dθ = 50cosθ mm/s dt dt dv a= dt a = 50cosθ d 2θ ⎛ dθ ⎞ two − 50sin θ ⎜ ⎟ mm/s dt � dt two ⎝ either cosθ sama dengan 0 big t =1s a couple of

When sixth is v = 0,

or

dθ =1− to = 0 dt More than 0 ≤ t ≤ 2 s, values of cosθ will be: t (s) 0 0 1 . 0 0. your five

1 . 0 0. a few 0. 878

1 . your five 0. 375 0. 981

2 . 0 0 1 . 0

θ ( rad )

cosθ

0. 375 0. 931

No alternatives cosθ = 0 in this range.

For t sama dengan 1 s,

θ = 1 − ( 0. 5 )(1) = 0. 5 rad

x = 50sin ( 0. your five ) by = twenty four. 0 mm a sama dengan − 43. 9 mm/s 2 a = 50cos ( 0. 5 )( −1) − 50sin ( 0. your five )( 0 )

two

Vector Technicians for Technical engineers: Statics and Dynamics, 8/e, Ferdinand L. Beer, At the. Russell Johnston, Jr., Elliot R. Eisenberg, William Elizabeth. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

NATUREL: Complete Online Solutions Manual Organization Program

Chapter 14, Solution 7.

Given:

Separate twice. x = to 3 − 6t a couple of + 9t + your five v= a= (a) When ever velocity is usually zero. dx = 3t 2 − 12t & 9 dt dv sama dengan 6t − 12 dt

v=0

3t 2 − 12t + 9 sama dengan 3 ( t − 1)( to − 3) = 0 t sama dengan 1 h and t = 3 s (b) Position by t = 5 s i9000. x5 = ( five ) − ( 6 )( five ) & ( 9 )( a few ) + 5

3 2

x5 =...

19.08.2019

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